x^2-150x+1400=0

Solution for x^2-150x+1400=0 equation:

x^2-150x+1400=0

a = 1; b = -150; c = +1400;
Δ = b2-4ac
Δ = -1502-4·1·1400
Δ = 16900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16900}=130$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-150)-130}{2*1}=\frac{20}{2}
=10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-150)+130}{2*1}=\frac{280}{2}
=140
$